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题目:先化简再求值?

问题描述:

1.(2a2-b)-(a2-4b)-(b+c)其中:a=1/3 b=1/2 c=12.2(x3-2y2)-(x-2y)-(x-3y2+2x3)其中:x=-3 y=-2



最佳答案:

1、(2a2-b)-(a2-4b)-(b+c)

=(2a2-a2)+(4b-b-b)-c

=a2+2b-c

=(1/3)2+2×(1/2)-1

=1/9+1-1

=1/9

2、2(x3-2y2)-(x-2y)-(x-3y2+2x3)

=2x3-4y2-x+2y-x+3y2-2x3

= -y2-2x+2y

将x=﹣3,y=﹣2代入“-y2-2x+2y”,得:

-y2-2x+2y

=-(-2)2-2(-3)+2(-2)

= -4+6-4

= ﹣2

? ?
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