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题目:已知:(1)2Fe(s)+O2(g)=2FeO(s)△H=-544kJ•mol-1(2)2Al(s)+32O2(g)=Al2O3(s)△H=-1675kJ•mol-1则2Al(s)+3FeO(s)=A

问题描述:

已知:(1)2Fe(s)+O2(g)=2FeO(s)△H=-544kJ•mol-1(2)2Al(s)+
3
2
O2(g)=Al2O3(s)△H=-1675kJ•mol-1则 2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)的△H为(  )A.-2491 kJ•mol-1B.+859 kJ•mol-1C.-1403 kJ•mol-1D.-859 kJ•mol-1
最佳答案:

已知:(1)2Fe(s)+O2(g)=2FeO(s)△H=-544kJ•mol-1(2)2Al(s)+

3
2
O2(g)=Al2O3(s)△H=-1675kJ•mol-1据盖斯定律,(2)-(1)×
3
2
得:2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)△H=-859KJ/mol故选:D
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